WebMar 28, 2024 · It is given that the current through the galvanometer is 0.2% of the main current. Mathematically, I G = 0.2 % of I ⇒ I G = 0.2 100 × I ∴ I G = 0.002 I So, naturally, the … WebJan 22, 2024 · In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer - YouTube...
In an ammeter 0.2% of main current passes through the …
WebAug 15, 2024 · In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance ... (C) 1/500 G (D) 500/499 G WebDec 23, 2024 · In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be. (a) 1/499 G. (b) … d1 wrestling championship 2021
In an ammeter 0.2 % of the main current passes through the …
WebIn an ammeter 0.2% of the main current passes through the galvanometer. If resis†an ce of galvanometer is G, the resis†an ce of ammeter will be? Open in App Solution Suggest Corrections 0 Similar questions Q. In an ammeter 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be WebThe other The injected secondary electrons current at the outer metallized one is the leakage current, controlled by the equivalent capillary surface now no longer exceeded the injected beam resistance R = (4.4 ± 1.4) × 1014 of the two resistors (in current I , while still dominating the extremely low leakage parallel) between the grounded ... WebIn an ammeter 0.2 % of the main current passes through the galvanometer. If resistance of galvanometer is G, the resistance of ammeter will be, 1/499 G 499/500 G 1/500 G 1/500 G 2526 Views Switch Flag Bookmark Advertisement Determine the current drawn from a 12 V supply with internal resistance 0.5 Ω by the infinite network shown in figure. d1 wrestling finals