WebThe formula for finding the n-th term of an AP is: an = a + (n − 1) × d Where a = First term d = Common difference n = number of terms a n = nth term Example: Find the nth term of AP: 1, 2, 3, 4, 5…., an, if the number of terms are 15. Solution: Given, AP: 1, 2, 3, 4, 5…., an n=15 By the formula we know, a n = a+ (n-1)d First-term, a =1 WebThe sum of the first term alone is 3 ⋅ 1 + 2 ⋅ 1 2 = 5. So the first term is 5. The sum of the first two terms is 3 ⋅ 2 + 2 ⋅ 2 2 = 14, so the second term is 14 − 5 = 9. The sum of the first …
If Sn = 2n^2 + 3n. Find 16th term of AP - teachoo
WebAn arithmetic progression or arithmetic sequence (AP) is a sequence of numbers such that the difference from any succeeding term to its preceding term remains constant throughout the sequence. The constant difference is called common difference of that arithmetic progression. For instance, the sequence 5, 7, 9, 11, 13, 15, . . . is an arithmetic progression … Webin an AP the sum of first n terms is 3n2/2 + 13n/2 Solution Verified by Toppr Was this answer helpful? 0 0 Similar questions The first term of two APs are equal and the ratios of … high voltage high current mosfet
The sum of the first n terms of an AP is given by Sn = (3n^2 – n).
WebMar 30, 2024 · There are 2 AP s with different first term and common difference For the first AP Let first term be a common difference be d Sum of n term = Sn = /2 (2a + (n 1)d) & nth term = an = a + (n 1)d Similarly for second AP Let first term = A common difference = D Sn = /2 (2A + (n 1)D) & nth term = An = A + (n 1)D We need to find ratio of 12th term i.e. … WebThe sum of n terms of an AP can be found using one of the following formulas: S n = n/2 (2a+ (n−1)d) S n = n/2 (a 1 +a n) Here, a = a 1 = the first term, d = the common difference, n = number of terms, a n = n th term, S n … WebAug 9, 2024 · It is an arithmetic progression with first term as 5 and common difference as 6 and 20^(th) term is 119 As sum of n terms of a certain series is given by S_n=2n+3n^2, Sum of 20 terms is 2×20+3×20^2=40+1200=1240. Further, sum of 19 terms is 2×19+3×19^2=38+1083=1121,. Hence 20^(th) term is 1240-1121=119. As sum of 1 term … high voltage high frequency